If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
x+3 = 0
x-1 = 0
x+3 = 0
x+3 = 0
x+3 = 0 // - 3
x = -3
x-1 = 0
x-1 = 0
x-1 = 0 // + 1
x = 1
x in (-oo:-3) U (-3:1) U (1:+oo)
(3*x^2+10*x+3)/(x+3) = (x^2-(4*x)+3)/(x-1) // - (x^2-(4*x)+3)/(x-1)
(3*x^2+10*x+3)/(x+3)-((x^2-(4*x)+3)/(x-1)) = 0
(3*x^2+10*x+3)/(x+3)-((x^2-4*x+3)/(x-1)) = 0
(3*x^2+10*x+3)/(x+3)+(-1*(x^2-4*x+3))/(x-1) = 0
((3*x^2+10*x+3)*(x-1))/((x+3)*(x-1))+(-1*(x^2-4*x+3)*(x+3))/((x+3)*(x-1)) = 0
(3*x^2+10*x+3)*(x-1)-1*(x^2-4*x+3)*(x+3) = 0
2*x^3+8*x^2+2*x-12 = 0
2*x^3+8*x^2+2*x-12 = 0
2*(x^3+4*x^2+x-6) = 0
x^3+4*x^2+x-6 = 0
{ 1, -1, 2, -2, 3, -3, 6, -6 }
1
x = 1
x^3+4*x^2+x-6 = 0
1
x-1
x^2+5*x+6
x^3+4*x^2+x-6
x-1
x^2-x^3
5*x^2+x-6
5*x-5*x^2
6*x-6
6-6*x
0
x^2+5*x+6 = 0
DELTA = 5^2-(1*4*6)
DELTA = 1
DELTA > 0
x = (1^(1/2)-5)/(1*2) or x = (-1^(1/2)-5)/(1*2)
x = -2 or x = -3
x in { -3, -2, 1}
2*(x+3)*(x+2)*(x-1) = 0
(2*(x+3)*(x+2)*(x-1))/((x+3)*(x-1)) = 0
(2*(x+3)*(x+2)*(x-1))/((x+3)*(x-1)) = 0 // * (x+3)*(x-1)
2*(x+3)*(x+2)*(x-1) = 0
( x+2 )
x+2 = 0 // - 2
x = -2
( x+3 )
x+3 = 0 // - 3
x = -3
( x-1 )
x-1 = 0 // + 1
x = 1
x in { -3}
x in { 1}
x = -2
| 12(7/3)=s | | (x-4y)-4= | | 32=.5cd | | t+18=27 | | 35=.5*10d | | 11(c-10)=12 | | (125-(x-20))x-75x=y | | 4256=165x+2771 | | 3/2x=17 | | 2=x-7 | | 3x+8=4x-12 | | 8=3.14d | | 6x-3y=45 | | 1.4q-7.6q+1.4=-11 | | 8=piD | | x+21/2=38 | | (-5+x)(3x+6)(2x+-4)=0 | | (x^2)+7x+140-10x=180 | | (x-5)(3x+6)(2x-4)=0 | | 7x-3=5x+5 | | 21+x/2=38 | | r-2=5 | | -.5x+5y=3 | | 5x-5=(x+1) | | 9+n=16 | | -.5y+5x=3 | | 6=m-2 | | (x-7)/5+2=(x+8)/10 | | 1/3(b+6)1/4+8 | | 11u/6=u+14 | | -41/60+17/20=29/30 | | x+.4y=7 |